Hi!
I have a Kustom 3x15' cabinet, model 3-15 B, ¸and I was wondering if it were a 4 or 8 ohm cabinet... I baught it used with a 250 head, both originals from 1970, and the head only have a 4 ohm output. So I guess that the cabinet is 4ohm too? How is it configured? 3x 8ohm speakers in paralell?
Thanks!
Optyk Messages: 125 Registered: August 2006 Location: Texas
Senior Member
If I remember my math correctly, the formula is
1/ohmage + 1/ohmage + 1/ohmage = 1/x (where x = the actual load in ohms)
Taking that further, with 16's, you'd get
1/16 + 1/16 + 1/16 = 3/16 = 1/5.33333 so x = 5.33333 ohms total load
With 8's, you'd have:
1/8 + 1/8 + 1/8 = 3/8 = 1/2.66667 so x = 2.66667 ohms total load. This would be too low of a load for your amp.
I just built my "Shure Thang" kustom/peavey/shure contraption. the speakers I put in it were two 10's at 16 ohms each and one 8 at 8 ohms. If I calculated correctly, then I'd get
1/16 + 1/16 + 1/8 = 1/16 + 1/16 + 2/16 = 4/16 = 1/4, so x = 4 ohms total load. If I'm out to lunch on all this, someone straighten me out quickly before I have a problem. So far, it's all worked perfectly. I haven't been running those internal speakers actually. I have a pair of Crate small PA speakers rated at 8 ohms each and that's what I'm actually running instead of the internals.
I guess I should also mention that all of the above pertains to speakers wired in parallel, not series. In series, I believe it's very simple, you simply total up the ohmage of the three speakers and that's your load. So, in my case, 16 + 16 + 8 = 40 ohms wired in series. Not a workable situation.
Rod
There's only two kinds of music. . . . blues and zippity doo dah.
stevem Messages: 4742 Registered: June 2004 Location: NY
Senior Member
A easyer way to figure dissimilar impeadance or resistance in parallel is this.
a 16 ohm and 4 ohm driver are being used.
16 X 4=64
16 + 4=20
64 DIVIDED BY 20= 3.2 OHm.
This works for how ever many drivers or resistors you have in parallel.
Optyk Messages: 125 Registered: August 2006 Location: Texas
Senior Member
I had forgotten about that method, steve. Like I said, it's been a long time since I took some electronics and used those formulae on a day to day basis. Leave it to me to use the hard way. LOL
Rod
There's only two kinds of music. . . . blues and zippity doo dah.
C4ster Messages: 686 Registered: June 2001 Location: Mukwonago, WI (Milwaukee...
Senior Member
No, product over sum only works for 2 resistors. The impedance is 2.6666 ohms. The reciprocal method is used for more than 2. However you can group 2 and then group another 2 so 8X8/8+8=64/16=4 then 4x8/4+8=32/12=2.6666, That could work for any number.
Conrad